n^2-(1-k)n=40

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Solution for n^2-(1-k)n=40 equation:


Simplifying
n2 + -1(1 + -1k) * n = 40

Reorder the terms for easier multiplication:
n2 + -1n(1 + -1k) = 40
n2 + (1 * -1n + -1k * -1n) = 40

Reorder the terms:
n2 + (1kn + -1n) = 40
n2 + (1kn + -1n) = 40

Reorder the terms:
1kn + -1n + n2 = 40

Solving
1kn + -1n + n2 = 40

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add 'n' to each side of the equation.
1kn + -1n + n + n2 = 40 + n

Combine like terms: -1n + n = 0
1kn + 0 + n2 = 40 + n
1kn + n2 = 40 + n

Add '-1n2' to each side of the equation.
1kn + n2 + -1n2 = 40 + n + -1n2

Combine like terms: n2 + -1n2 = 0
1kn + 0 = 40 + n + -1n2
1kn = 40 + n + -1n2

Divide each side by '1n'.
k = 40n-1 + 1 + -1n

Simplifying
k = 40n-1 + 1 + -1n

Reorder the terms:
k = 1 + 40n-1 + -1n

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